How do you count pi bonds on ring structures?
November 21st, 2008 | by bonds |Journey asked:
My teacher has given us several ring compounds and we have to determine the number of pi bonds. One ring has two double bonds and within the ring there are an oxygen with two lone pairs and a nitrogen with one lone pair. Oxygen is attached by single bonds on the ring while nitrogen is a attached by one single bond and one double bond. Does that make any sense? So its a cyclopentene but two of the carbons have been switched out with an oxygen and a nitrogen. Please HELP!
LOYD
My teacher has given us several ring compounds and we have to determine the number of pi bonds. One ring has two double bonds and within the ring there are an oxygen with two lone pairs and a nitrogen with one lone pair. Oxygen is attached by single bonds on the ring while nitrogen is a attached by one single bond and one double bond. Does that make any sense? So its a cyclopentene but two of the carbons have been switched out with an oxygen and a nitrogen. Please HELP!
LOYD














One Response to “How do you count pi bonds on ring structures?”
By Tamika M on Nov 23, 2008 | Reply
JODY
Using Valence Bond Theory:
-Single bond = 1 sigma bond
-Double bond = 1 sigma bond + 1 pi bond
-Triple bond = 1 sigma bond + 2 pi bonds
So the compound you are describing has 2 pi bond.
Hope this helps